Wednesday, April 15, 2015
Saturday, July 26, 2014
TNPSC GROUP 2 MATHS QUESTIONS WITH ANSWERS
1. The
circle graph given here shows the spending of a country on various sports
during a particular year. Study the graph and answer the question.
What
percentage of the total spending is spent on Tennis?
A.
12.5%
B.
22.5%
C.25%
D.45%
ANS: A
EXPLANATION:
(45/360)×100=12.5%
2. Malini deposited
Rs.7000/- with a finance company for 3 years at an interest of 15% per annum.
What is the compound interest and the amount that Malini will get after 3
years?
A.
C.I – Rs.3246, amount – Rs.13246
B.
C.I – Rs.3646, amount – Rs.10646
C.
C.I – Rs.6436, amount – Rs.16046
D.
C.I – Rs.4636, amount – Rs.14636
ANS: B
EXPLANATION:
Amount=
p×(1+r/100)n
=7000×(1+15/100)3
=7000×(115/100)3
=7000×(23/20)3
=10646
C.I=10646-7000=3646
3. The average salary of
all workers in the factory is Rs.60. The average of salary of 12 officers is
Rs.400. The average salary of rest is Rs.56. Find the total no of workers in
the factory.
A.
1116
B.
1032
C.
1212
D.
1132
ANS: B
EXPLANATION:
12×400+X×56
= (12+X)×60
4800+56X
= 720+60X
4X
= 4080
X
= 1020
Total
no of workers = 12+X=12+1020=1032
4. The sides of a
triangle are in the ration ½: 1/3: 1/4 and its perimeter is 104 cm. The length
of longest side is
A.
52 cm
B.
48 cm
C.
32 cm
D.
26 cm
ANS: B
EXPLANATION:
LCM
of 2,3,4 = 12
Therefore
½:1/3:1/4 = 6/12:4/12:3/12 = 6:4:3
6x+4x+3x
= 104
13x
= 104
x
= 8
Longest
side = 6x=48
5. If A’s salary is 20%
less than B’s salary, by how much percent B’s salary more than A’s?
A.
24%
B.
25%
C.
20%
D.
22%
ANS: B
EXPLANATION:
[20/(100-20)]
× 100 =[ 20/80]×100=25%
6. The volume of a cube
is 125 cm3. The surface area of the cube is
A.
625 cm2
B.
125 cm2
C.
150 cm2
D.
100 cm2
ANS: C
EXPLANATION:
a3=125
a=5
Surface
area = 6a2=6×25=150cm2
7. If 50% of (x-y)=30% of (x+y) then what percent
of x is y?
A.
25%
B.
50%
C.
75%
D.
100%
ANS: A
EXPLANATION:
50/100
(X-Y) = 30/100 (X+Y)
1/2
(X-Y) = 3/10 (X+Y)
½
X - 3/10 X = 3/10 Y + 1/2 Y
2/10
X = 8/10 Y
Y
= ¼ X
¼=
25%
8. 30 percent of a
number is 15 less than 3/5th of a number. What is the number?
A.
48
B.
52
C.
50
D.
70
ANS: C
EXPLANATION:
30/100
X = 3/5 X – 15
3/10 X – 3/5 X = 15
3/10
X = 15
X
= 50
9. The least number
which when increased by 1 is divisible by 12,18,24,32 is
A.
278
B.
288
C.
287
D.
279
ANS: C
EXPLANATION:
Required
number = [L.C.M of 12, 18, 24, 32] – 1
= 288 -1
=
287
10. The missing term in
the series 9, 225, 16, 196, 25, 169, ___, 144
A.
81
B.
121
C.
36
D.
49
ANS: C
EXPLANATION:
9, 225, 16, 196, 25, 169, ___, 144
32, 225, 42,
196, 52,169, 62,
144
62
= 36
10.
Find x in 4x × 642x = 16x+5
A.
1
B.
5
C.
4
D.
2
ANS: D
EXPLANATION:
4x
× (43)2x = (42) x+5
4x
× 46x = 42x+10
4x+6x
= 42x+10
x
+ 6x = 2x+10
5x
= 10
x=2
11. At simple interest
Rs. 1000 becomes Rs. 1150 in 3 years. If the interest rate is increased by 3%
then the total amount is
A.
1400
B.
1300
C.
1140
D.
1240
ANS: D
EXPLANATION:
S.I
= 1150 – 1000 = 150
PNR/100
= 150
(1000×3×R)
/100= 150
R
= 5
R
is increased by 3%, new R = 5+3 = 8%
New
S.I = (1000×3×8)/100 = 240
Amount
= 1240
12. If 7 spiders make 7
webs in 7 days, then 1 spider will make 1 web in how many days?
A.
1
B.
7/2
C.
7
D.
49
ANS: C
EXPLANATION:
SPIDERS
|
DAYS
|
WEBS
|
7
|
7
|
7
|
7
|
1
|
1
|
1
|
1
|
1/7
|
Therefore
it will take 7 days.
13. The following table
gives the life time of 500 CFL lamps:
Life time (months)
|
9
|
10
|
11
|
12
|
13
|
14
|
More
than 14
|
Total
|
Number of lamps
|
26
|
71
|
82
|
102
|
89
|
77
|
53
|
500
|
A
bulb is selected at random. The probability that the life time of the selected
bulbatmost 11 months is given by
A.
82/500
B.
179/500
C.
97/500
D. 268/500
ANS: B
EXPLANATION:
(26+71+82)/500
= 179/500
14. Find the missing
term in the diagram
4
|
5
|
10
|
8
|
12
|
8
|
||
20
|
9
|
80
|
18
|
?
|
20
|
A.
25
B.
30
C.
96
D. none of these
ANS: C
EXPLANATION:
4×5
= 20
10×8
= 80
12
× 8 = 96
15. The sum of three
prime numbers is 101. The difference of two of them is 24. What are the
numbers?
A.
5, 59, 37
B.
41, 53, 7
C.
11, 37, 53
D. 3, 61, 37
ANS: D
EXPLANATION:
Clue:
go with options.
3+61+37
= 101
61
– 37 = 24
16. If 18% of the total
number of oranges in a basket is 36. Then the total number of oranges is
A.
100
B.
150
C.
200
D. 300
ANS: C
EXPLANATION:
(36/18)×100
= 200
17. The ratio of the
prices of two cows was 23:16. Two years later the price of the first cow rises
by Rs.477 and that of the second by 10% and the ratio of their pries become
20:11. Find the original prices
A.
Rs. 1219, Rs. 848
B.
Rs. 1218, Rs. 848
C.
Rs. 1210, Rs. 850
D. Rs. 1219, Rs. 840
ANS: A
EXPLANATION:
(23X+477)
/ [16X + (10/100)] × 16X = 20/11
(23X+477)
× 11 = 20 × [16X + (16/10) X]
253X+477×11
= 320X + 32 X
253X+477×11
= 352X
99X
= 477×11
X=
477× 11/99
X
= 53
23X
= 23×53 = 1219
16X
= 16×53 = 848
18. A ladder of 25 ft
length reaches a window which is 24 ft above the ground level on one side of
the street. Keeping its foot at the same point the ladder is turned the other
side of the street and now reaches a window of 7 ft high. Then width of the
street
A.
30
B.
32
C.
29
D. 31
ANS: D
EXPLANATION:
According to Pythagoras theorem
a = root of (252- 242)=
root of (49)=7
b = root of (252- 72)=
root of (576)=24
|
Width of the street a + b=7+24 = 31
<---------Width------------>
Thursday, July 17, 2014
SPORTS CURRENT AFFAIRS
Next Winter Olympic 2018: PyeongChang, South Korea.
Raj Singh (Dronacharya winner) will be Chef De Mission for CWG 2014
Vijay Amritraj: Davis Cup commitment award. Billiards Saurav Kothari: national championship
Uber Cup Badminton.Held in Delhi. China won against Japan.
Thomas Cup 2014 (men only) Held in Delhi. Japan won first time.
Justice Mudgal panelIPL spot fixing. now Saurav Ganguly also joined the panel.
Col.CK Naidu lifetime achievementKapil Dev. Award by BCCI
Bhaichung Bhutiya Contested Lok Shabha election from Trniamool ticket in Darjeeling but defeated.
courtesy: mrunal.org
Raj Singh (Dronacharya winner) will be Chef De Mission for CWG 2014
Vijay Amritraj: Davis Cup commitment award. Billiards Saurav Kothari: national championship
Uber Cup Badminton.Held in Delhi. China won against Japan.
Thomas Cup 2014 (men only) Held in Delhi. Japan won first time.
Justice Mudgal panelIPL spot fixing. now Saurav Ganguly also joined the panel.
Col.CK Naidu lifetime achievementKapil Dev. Award by BCCI
Bhaichung Bhutiya Contested Lok Shabha election from Trniamool ticket in Darjeeling but defeated.
courtesy: mrunal.org
#TNPSC - #VAO (JUNE 2014) MATHS QUESTIONS(SOLVED):
1. If the SIMPLE interest for an amount at 4% per annum for 3 years is Rs.1200. Find the COMPOUND interest at the same rate for the same amount for 2 years.
A. Rs.10116
B. Rs.10720
C. Rs.10616
D. Rs.816
Ans: D
Explanation:
S.I for 3 years =1200
S.I for 1 year =1200/3=400
C.I for 2 years =400+[400+400*(4/100)]
=400+416=816
2. Which of the following is/are true?
(i) ax=bx-->a=b
(ii) x/a=x/b-->a=b
(iii) a=b-->ax=bx
(iv) a+x=b+x-->a=b
A. (i),(ii),(iii),(iv)
B. (i),(ii) and (iv) only
C. (i) and (iv) only
D. (iii) and (iv) only
Ans: D
Explanation:
(i) and (ii) are false if x=0(zero)
3. If + means *, - means +, * means /, / means - then the value of 84*28+8/10-9=
A. 23
B. 22
C. 30
D. 26
Ans: A
Explanation:
84/28*8-10+9 = 3*8-10+9 = 24-10+9=23
4. If the ratio of the ages of son and father in 2014 and 2022 are 1:4 and 3:8 respectively, then the SUM of the ages of son and father in 2010 is
A. 42
B. 43
C. 50
D. 45
Ans: A
Explanation:
2022-2014=8
1x+8 / 4x+8= 3x/8x
x+8/4x+8=3/8
8*(x+8)=3*(4x+8)
8x+64=12x+24
12x-8x=64-24
4x=40
x=10
There for SUM of ages of son and father in 2014 is X+4X=10+40=50
SUM of ages of son and father in "2010" is 50-(4+4)=42
5. Fine the volume of a largest sphere inscribed from the right circular cylindrical wood whose radius is 1 cm and height is 5 cm
A. 4/3 pi cm3
B. 5/16 pi cm3
C. 5 pi cm3
D. 8 pi cm3
Ans: A
Explanation:
The radius of largest sphere inscribed from the cylinder of radius 1 cm is also 1cm.
Therefore Volume = 4/3 pi r3
= 4/3 pi (1*1*1) cm3
=4/3 pi cm 3
6. The average of five numbers is 20. If we eliminate one number from it, the average will be reduced by 5. What is the number eliminated?
A.5
B. 40
C. 20
D. 15
Ans:B
Explanation:
5*20=100
4*15=60
100-60=40
7. The average of 50 students in 10th std class is 15 years. 10 more students are admitted afresh in the class and average age is increased by 0.5 years. The average age of newly joined students is
A. 15
B. 16
C. 17
D. 18
Ans: D
Explanation:
50*15=750
50+10 * 15*0.5=60*15.5=930
930-750=180
180/10=18
8. What percentage of students does not like computer science?
Subject - No. of students
Mathematics - 6
Physics - 12
Chemistry - 15
Biology - 8
Computer Science - 9
A. 91%
B. 9%
C. 82%
D. 18%
Ans: C
Explanation:
6+12+15+8+9=50
50-9=41
(41/50)*100=82%
9. In a set of first 'x' natural numbers there are 30 prime numbers. Find the number of composite numbers in the above set.
A. x-30
B. 30-x
C. x-29
D. x-31
Ans: D
Explanation:
Number of remaining numbers=x-30
BUT '1' IS NEITHER PRIME NOR COMPOSITE.
Therefore,
No of composite numbers = x-(30+1)=x-31
10. A number when divided by 2,3,4,5 and 6 leaves remainder, it is divisible by 7, the least possible number is
A. 117
B. 119
C. 113
D. 121
Ans: B
Clue: 119 is the only number which is divisible by 7.
11. A man saves Rs. 3000 per month from his total salary of Rs. 20000. The percentage of his savings is
A. 5%
B. 10%
C. 15%
D. 20%
Ans: C
Explanation:
(3000/20000) * 100=15
12. A seller says the cost of an item at a profit of 3%. Then he gives a discount of 3%. The he sells the item at
A. a profit of 0.09%
B. a loss of 0.09%
C. a profit of 9%
D. no loss or no profit
Ans: B
Explanation:
If both profit and discount are same then the result is loss.
Loss%= x2/100=(3*3)/100=9/100=0.09%
13. Find the sum of all natural numbers between 300 and 500 which are divisible by 11.
A.7337
B.7227
C.7447
D.7557
Ans: B
Explanation:
It makes an arithmetic progression.
Sum =1/2 n (a+l)
a- first term
l- last term
n- no of terms
In this case a=308 , b=495
( The smallest and largest numbers between 300-500 which are exactly divisible by 11)
To find n:
500-300=200
200/11 = 18 (Don't mind about remainder)
Therefore n=18
Substituting the values in the formula,
1/2 18 (308+495)=9*803=7227
14. Babu has 540 cakes. He wants to distribute then equally to some persons. IF THE NUMBER OF CAKES IS EQUAL TO 15% OF THE NUMBER OF PERSONS, find the number of cakes given to each person.
A.60
B.20
C.9
D.54
Ans: C
Explanation:
x= no of cakes, y= no of persons
540/x=y
but x=(15/100)y
540/ (15/100)y=y
y2=(540*100)/15=3600
y=60
x=540/60=9
Quick method:
Go with options:
(15/100)*60=9
1. If the SIMPLE interest for an amount at 4% per annum for 3 years is Rs.1200. Find the COMPOUND interest at the same rate for the same amount for 2 years.
A. Rs.10116
B. Rs.10720
C. Rs.10616
D. Rs.816
Ans: D
Explanation:
S.I for 3 years =1200
S.I for 1 year =1200/3=400
C.I for 2 years =400+[400+400*(4/100)]
=400+416=816
2. Which of the following is/are true?
(i) ax=bx-->a=b
(ii) x/a=x/b-->a=b
(iii) a=b-->ax=bx
(iv) a+x=b+x-->a=b
A. (i),(ii),(iii),(iv)
B. (i),(ii) and (iv) only
C. (i) and (iv) only
D. (iii) and (iv) only
Ans: D
Explanation:
(i) and (ii) are false if x=0(zero)
3. If + means *, - means +, * means /, / means - then the value of 84*28+8/10-9=
A. 23
B. 22
C. 30
D. 26
Ans: A
Explanation:
84/28*8-10+9 = 3*8-10+9 = 24-10+9=23
4. If the ratio of the ages of son and father in 2014 and 2022 are 1:4 and 3:8 respectively, then the SUM of the ages of son and father in 2010 is
A. 42
B. 43
C. 50
D. 45
Ans: A
Explanation:
2022-2014=8
1x+8 / 4x+8= 3x/8x
x+8/4x+8=3/8
8*(x+8)=3*(4x+8)
8x+64=12x+24
12x-8x=64-24
4x=40
x=10
There for SUM of ages of son and father in 2014 is X+4X=10+40=50
SUM of ages of son and father in "2010" is 50-(4+4)=42
5. Fine the volume of a largest sphere inscribed from the right circular cylindrical wood whose radius is 1 cm and height is 5 cm
A. 4/3 pi cm3
B. 5/16 pi cm3
C. 5 pi cm3
D. 8 pi cm3
Ans: A
Explanation:
The radius of largest sphere inscribed from the cylinder of radius 1 cm is also 1cm.
Therefore Volume = 4/3 pi r3
= 4/3 pi (1*1*1) cm3
=4/3 pi cm 3
6. The average of five numbers is 20. If we eliminate one number from it, the average will be reduced by 5. What is the number eliminated?
A.5
B. 40
C. 20
D. 15
Ans:B
Explanation:
5*20=100
4*15=60
100-60=40
7. The average of 50 students in 10th std class is 15 years. 10 more students are admitted afresh in the class and average age is increased by 0.5 years. The average age of newly joined students is
A. 15
B. 16
C. 17
D. 18
Ans: D
Explanation:
50*15=750
50+10 * 15*0.5=60*15.5=930
930-750=180
180/10=18
8. What percentage of students does not like computer science?
Subject - No. of students
Mathematics - 6
Physics - 12
Chemistry - 15
Biology - 8
Computer Science - 9
A. 91%
B. 9%
C. 82%
D. 18%
Ans: C
Explanation:
6+12+15+8+9=50
50-9=41
(41/50)*100=82%
9. In a set of first 'x' natural numbers there are 30 prime numbers. Find the number of composite numbers in the above set.
A. x-30
B. 30-x
C. x-29
D. x-31
Ans: D
Explanation:
Number of remaining numbers=x-30
BUT '1' IS NEITHER PRIME NOR COMPOSITE.
Therefore,
No of composite numbers = x-(30+1)=x-31
10. A number when divided by 2,3,4,5 and 6 leaves remainder, it is divisible by 7, the least possible number is
A. 117
B. 119
C. 113
D. 121
Ans: B
Clue: 119 is the only number which is divisible by 7.
11. A man saves Rs. 3000 per month from his total salary of Rs. 20000. The percentage of his savings is
A. 5%
B. 10%
C. 15%
D. 20%
Ans: C
Explanation:
(3000/20000) * 100=15
12. A seller says the cost of an item at a profit of 3%. Then he gives a discount of 3%. The he sells the item at
A. a profit of 0.09%
B. a loss of 0.09%
C. a profit of 9%
D. no loss or no profit
Ans: B
Explanation:
If both profit and discount are same then the result is loss.
Loss%= x2/100=(3*3)/100=9/100=0.09%
13. Find the sum of all natural numbers between 300 and 500 which are divisible by 11.
A.7337
B.7227
C.7447
D.7557
Ans: B
Explanation:
It makes an arithmetic progression.
Sum =1/2 n (a+l)
a- first term
l- last term
n- no of terms
In this case a=308 , b=495
( The smallest and largest numbers between 300-500 which are exactly divisible by 11)
To find n:
500-300=200
200/11 = 18 (Don't mind about remainder)
Therefore n=18
Substituting the values in the formula,
1/2 18 (308+495)=9*803=7227
14. Babu has 540 cakes. He wants to distribute then equally to some persons. IF THE NUMBER OF CAKES IS EQUAL TO 15% OF THE NUMBER OF PERSONS, find the number of cakes given to each person.
A.60
B.20
C.9
D.54
Ans: C
Explanation:
x= no of cakes, y= no of persons
540/x=y
but x=(15/100)y
540/ (15/100)y=y
y2=(540*100)/15=3600
y=60
x=540/60=9
Quick method:
Go with options:
(15/100)*60=9
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