Saturday, July 26, 2014

TNPSC GROUP 2 MATHS QUESTIONS WITH ANSWERS in PDF format

TNPSC GROUP 2 MATHS QUESTIONS WITH ANSWERS


1. The circle graph given here shows the spending of a country on various sports during a particular year. Study the graph and answer the question.

What percentage of the total spending is spent on Tennis?
A. 12.5%
B. 22.5%
C.25%
D.45%

ANS: A

EXPLANATION:

(45/360)×100=12.5%

2. Malini deposited Rs.7000/- with a finance company for 3 years at an interest of 15% per annum. What is the compound interest and the amount that Malini will get after 3 years?

A. C.I – Rs.3246, amount – Rs.13246
B. C.I – Rs.3646, amount – Rs.10646
C. C.I – Rs.6436, amount – Rs.16046
D. C.I – Rs.4636, amount – Rs.14636

ANS: B

EXPLANATION:

Amount= p×(1+r/100)n
=7000×(1+15/100)3
=7000×(115/100)3
=7000×(23/20)3
=10646

C.I=10646-7000=3646

3. The average salary of all workers in the factory is Rs.60. The average of salary of 12 officers is Rs.400. The average salary of rest is Rs.56. Find the total no of workers in the factory.

A. 1116
B. 1032
C. 1212
D. 1132

ANS: B

EXPLANATION:

12×400+X×56 = (12+X)×60
4800+56X = 720+60X
4X = 4080
X = 1020

Total no of workers = 12+X=12+1020=1032

4. The sides of a triangle are in the ration ½: 1/3: 1/4 and its perimeter is 104 cm. The length of longest side is

A. 52 cm
B. 48 cm
C. 32 cm
D. 26 cm

ANS: B

EXPLANATION:

LCM of 2,3,4 = 12
Therefore ½:1/3:1/4 = 6/12:4/12:3/12 = 6:4:3

6x+4x+3x = 104
13x = 104
x = 8

Longest side = 6x=48

5. If A’s salary is 20% less than B’s salary, by how much percent B’s salary more than A’s?

A. 24%
B. 25%
C. 20%
D. 22%

ANS: B

EXPLANATION:

[20/(100-20)] × 100 =[ 20/80]×100=25%

6. The volume of a cube is 125 cm3. The surface area of the cube is

A. 625 cm2
B. 125 cm2
C. 150 cm2
D. 100 cm2

ANS: C

EXPLANATION:

a3=125
a=5

Surface area = 6a2=6×25=150cm2

7.  If 50% of (x-y)=30% of (x+y) then what percent of x is y?

A. 25%
B. 50%
C. 75%
D. 100%

ANS: A

EXPLANATION:

50/100 (X-Y) = 30/100 (X+Y)
1/2 (X-Y) = 3/10 (X+Y)
½ X - 3/10 X = 3/10 Y + 1/2 Y
2/10 X = 8/10 Y
Y = ¼ X
¼= 25%

8. 30 percent of a number is 15 less than 3/5th of a number. What is the number?

A. 48
B. 52
C. 50
D. 70

ANS: C

EXPLANATION:

30/100 X = 3/5 X – 15
 3/10 X – 3/5 X = 15
3/10 X = 15
X = 50

9. The least number which when increased by 1 is divisible by 12,18,24,32 is

A. 278
B. 288
C. 287
D. 279

ANS: C

EXPLANATION:

Required number = [L.C.M of 12, 18, 24, 32] – 1
                        = 288 -1
= 287

10. The missing term in the series 9, 225, 16, 196, 25, 169, ___, 144

A. 81
B. 121
C. 36
D. 49

ANS: C

EXPLANATION:

9, 225, 16, 196, 25, 169, ___, 144
32, 225, 42, 196, 52,169, 62, 144
62 = 36

10. Find x in 4x × 642x = 16x+5

A. 1
B. 5
C. 4
D. 2

ANS: D

EXPLANATION:

4x × (43)2x = (42) x+5
4x × 46x = 42x+10
4x+6x = 42x+10
x + 6x = 2x+10
5x = 10
x=2

11. At simple interest Rs. 1000 becomes Rs. 1150 in 3 years. If the interest rate is increased by 3% then the total amount is

A. 1400
B. 1300
C. 1140
D. 1240

ANS: D

EXPLANATION:

S.I = 1150 – 1000 = 150
PNR/100 = 150
(1000×3×R) /100= 150
R = 5

R is increased by 3%, new R = 5+3 = 8%
New S.I = (1000×3×8)/100 = 240
Amount = 1240

12. If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?

A. 1
B. 7/2
C. 7
D. 49

ANS: C

EXPLANATION:

SPIDERS
DAYS
WEBS
7
7
7
7
1
1
1
1
1/7

Therefore it will take 7 days.

13. The following table gives the life time of 500 CFL lamps:

Life time (months)
9
10
11
12
13
14
More than 14
Total
Number of lamps
26
71
82
102
89
77
53
500

A bulb is selected at random. The probability that the life time of the selected bulbatmost 11 months is given by

A. 82/500
B. 179/500
C. 97/500
D. 268/500
ANS: B

EXPLANATION:

(26+71+82)/500 = 179/500

14. Find the missing term in the diagram

4
5

10
8

12
8
20
9
80
18
?
20

A. 25
B. 30
C. 96
D. none of these
ANS: C

EXPLANATION:

4×5 = 20
10×8 = 80
12 × 8 = 96

15. The sum of three prime numbers is 101. The difference of two of them is 24. What are the numbers?

A. 5, 59, 37
B. 41, 53, 7
C. 11, 37, 53
D. 3, 61, 37
ANS: D

EXPLANATION:
Clue: go with options.
3+61+37 = 101
61 – 37 = 24

16. If 18% of the total number of oranges in a basket is 36. Then the total number of oranges is

A. 100
B. 150
C. 200
D. 300
ANS: C

EXPLANATION:
(36/18)×100 = 200

17. The ratio of the prices of two cows was 23:16. Two years later the price of the first cow rises by Rs.477 and that of the second by 10% and the ratio of their pries become 20:11. Find the original prices

A. Rs. 1219, Rs. 848
B. Rs. 1218, Rs. 848
C. Rs. 1210, Rs. 850
D. Rs. 1219, Rs. 840
ANS: A

EXPLANATION:

(23X+477) / [16X + (10/100)] × 16X = 20/11
(23X+477) × 11 = 20 × [16X + (16/10) X]
253X+477×11 = 320X + 32 X
253X+477×11 = 352X
99X = 477×11
X= 477× 11/99
X = 53

23X = 23×53 = 1219
16X = 16×53 = 848

18. A ladder of 25 ft length reaches a window which is 24 ft above the ground level on one side of the street. Keeping its foot at the same point the ladder is turned the other side of the street and now reaches a window of 7 ft high. Then width of the street

A. 30
B. 32
C. 29
D. 31
ANS: D

EXPLANATION:
According to Pythagoras theorem
a = root of (252- 242)= root of (49)=7
b = root of (252- 72)= root of (576)=24
  





 Width of the street a + b=7+24 = 31


<---------Width------------>





Thursday, July 17, 2014

SPORTS CURRENT AFFAIRS

Next Winter Olympic 2018: PyeongChang, South Korea.

 Raj Singh (Dronacharya winner) will be Chef De Mission for CWG 2014

 Vijay Amritraj: Davis Cup commitment award. Billiards Saurav Kothari: national championship

 Uber Cup Badminton.Held in Delhi. China won against Japan.

Thomas Cup 2014 (men only) Held in Delhi. Japan won first time.

 Justice Mudgal panelIPL spot fixing. now Saurav Ganguly also joined the panel.

 Col.CK Naidu lifetime achievementKapil Dev. Award by BCCI

 Bhaichung Bhutiya Contested Lok Shabha election from Trniamool ticket in Darjeeling but defeated. 

courtesy: mrunal.org
#TNPSC - #VAO (JUNE 2014) MATHS QUESTIONS(SOLVED):

1. If the SIMPLE interest for an amount at 4% per annum for 3 years is Rs.1200. Find the COMPOUND interest at the same rate for the same amount for 2 years.
A. Rs.10116
B. Rs.10720
C. Rs.10616
D. Rs.816

Ans: D
Explanation:
S.I for 3 years =1200
S.I for 1 year =1200/3=400
C.I for 2 years =400+[400+400*(4/100)]
=400+416=816

2. Which of the following is/are true?
(i) ax=bx-->a=b
(ii) x/a=x/b-->a=b
(iii) a=b-->ax=bx
(iv) a+x=b+x-->a=b

A. (i),(ii),(iii),(iv)
B. (i),(ii) and (iv) only
C. (i) and (iv) only
D. (iii) and (iv) only

Ans: D
Explanation:
(i) and (ii) are false if x=0(zero)

3. If + means *, - means +, * means /, / means - then the value of 84*28+8/10-9=
A. 23
B. 22
C. 30
D. 26

Ans: A
Explanation:
84/28*8-10+9 = 3*8-10+9 = 24-10+9=23

4. If the ratio of the ages of son and father in 2014 and 2022 are 1:4 and 3:8 respectively, then the SUM of the ages of son and father in 2010 is
A. 42
B. 43
C. 50
D. 45

Ans: A
Explanation:
2022-2014=8
1x+8 / 4x+8= 3x/8x
x+8/4x+8=3/8
8*(x+8)=3*(4x+8)
8x+64=12x+24
12x-8x=64-24
4x=40
x=10
There for SUM of ages of son and father in 2014 is X+4X=10+40=50
SUM of ages of son and father in "2010" is 50-(4+4)=42

5. Fine the volume of a largest sphere inscribed from the right circular cylindrical wood whose radius is 1 cm and height is 5 cm 
A. 4/3 pi cm3
B. 5/16 pi cm3
C. 5 pi cm3
D. 8 pi cm3

Ans: A
Explanation:
The radius of largest sphere inscribed from the cylinder of radius 1 cm is also 1cm.
Therefore Volume = 4/3 pi r3
= 4/3 pi (1*1*1) cm3
=4/3 pi cm 3 

6. The average of five numbers is 20. If we eliminate one number from it, the average will be reduced by 5. What is the number eliminated?
A.5
B. 40
C. 20
D. 15

Ans:B
Explanation:
5*20=100
4*15=60
100-60=40

7. The average of 50 students in 10th std class is 15 years. 10 more students are admitted afresh in the class and average age is increased by 0.5 years. The average age of newly joined students is
A. 15
B. 16
C. 17
D. 18

Ans: D
Explanation:
50*15=750
50+10 * 15*0.5=60*15.5=930
930-750=180
180/10=18

8. What percentage of students does not like computer science?
Subject - No. of students
Mathematics - 6
Physics - 12
Chemistry - 15
Biology - 8
Computer Science - 9
A. 91%
B. 9%
C. 82%
D. 18%

Ans: C
Explanation:
6+12+15+8+9=50
50-9=41
(41/50)*100=82%

9. In a set of first 'x' natural numbers there are 30 prime numbers. Find the number of composite numbers in the above set.
A. x-30
B. 30-x
C. x-29
D. x-31

Ans: D
Explanation:
Number of remaining numbers=x-30
BUT '1' IS NEITHER PRIME NOR COMPOSITE.
Therefore,
No of composite numbers = x-(30+1)=x-31

10. A number when divided by 2,3,4,5 and 6 leaves remainder, it is divisible by 7, the least possible number is
A. 117
B. 119
C. 113
D. 121

Ans: B
Clue: 119 is the only number which is divisible by 7.

11. A man saves Rs. 3000 per month from his total salary of Rs. 20000. The percentage of his savings is
A. 5%
B. 10%
C. 15%
D. 20%

Ans: C
Explanation:
(3000/20000) * 100=15

12. A seller says the cost of an item at a profit of 3%. Then he gives a discount of 3%. The he sells the item at
A. a profit of 0.09%
B. a loss of 0.09%
C. a profit of 9%
D. no loss or no profit

Ans: B
Explanation:
If both profit and discount are same then the result is loss.
Loss%= x2/100=(3*3)/100=9/100=0.09%

13. Find the sum of all natural numbers between 300 and 500 which are divisible by 11.
A.7337
B.7227
C.7447
D.7557

Ans: B
Explanation:
It makes an arithmetic progression.
Sum =1/2 n (a+l) 
a- first term
l- last term
n- no of terms

In this case a=308 , b=495 
( The smallest and largest numbers between 300-500 which are exactly divisible by 11)

To find n:
500-300=200
200/11 = 18 (Don't mind about remainder)
Therefore n=18

Substituting the values in the formula,
1/2 18 (308+495)=9*803=7227

14. Babu has 540 cakes. He wants to distribute then equally to some persons. IF THE NUMBER OF CAKES IS EQUAL TO 15% OF THE NUMBER OF PERSONS, find the number of cakes given to each person.
A.60
B.20
C.9
D.54

Ans: C
Explanation:
x= no of cakes, y= no of persons
540/x=y
but x=(15/100)y
540/ (15/100)y=y
y2=(540*100)/15=3600
y=60
x=540/60=9

Quick method:
Go with options:
(15/100)*60=9